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Quiz: Line Chart-1

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Number of Questions: 3

Question: 1 -

Directions to Solve

In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.

Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.

Maximum Total Marks in each Periodical Exam = 500

What are the average marks obtained by the student in all the periodical exams during the last session ?

Options:

  1. 379

  2. 373

  3. 381

  4. 385

    5. Answer:

    381
    Solution:

    Average marks obtained in all the periodical exams

        = 1 x [360 + 365 + 370 + 385 + 400 + 405] = 380.83 ~= 381.
    6

Question: 2 -

Directions to Solve

In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.

Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.

Maximum Total Marks in each Periodical Exam = 500

The total number of marks obtained in Feb. 02 is what percent of the total marks obtained in April 01 ?

Options:

  1. 116.5%

  2. 110%

  3. 112.5%

  4. 115%
    5. Answer:

    112.5%
    Solution:

    Here it is clear from the graph that the student obtained 360, 365, 370, 385, 400 and 405 marks in periodical exams held in Apr 01, Jun 01, Aug 01, Oct 01, Dec 01 and Feb 02 respectively.

    Required percentage = ( 405 x 100 ) % = 112.5%.
    360

Question: 3 -

Directions to Solve

In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.

Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.

Maximum Total Marks in each Periodical Exam = 500

In which periodical exams did the student obtain the highest percentage increase in marks over the previous periodical exams ?

Options:

  1. Oct, 01

  2. August, 01

  3. Dec, 01

  4. June, 01

    5. Answer:

    Oct, 01
    Solution:

    Percentage increase in marks in various periodical exams compared to the previous exams are:

    For Jun 01 = [ (365 - 360) x 100 ] % = 1.39%.
    360
    For Aug 01 = [ (370 - 365) x 100 ] % = 1.37%.
    365
    For Oct 01 = [ (385 - 370) x 100 ] % = 4.05%.
    370
    For Dec 01 = [ (400 - 385) x 100 ] % = 3.90%.
    385
    For Feb 02 = [ (404 - 400) x 100 ] % = 1.25%.
    400

    Clearly, highest percentage increase in marks is in Oct 01.